Register
Elemental analysis of a compound, once used as a pesticide, was found to be 74.2% carbon, 8.64% hydrogen, and 17.2% nitrogen. What is the empirical formula of this compound?
208k views
3 votes
Elemental analysis of a compound, once used as a pesticide, was found to be 74.2% carbon, 8.64% hydrogen, and 17.2% nitrogen. What is the empirical formula of this compound?

User Gogson
by
7.6k points

1 Answer

3 votes
74.2/16.00=4.6381.432=3.2*4=13
8.64/1.01=8.554/1.432=5.9=6*4=24
17.2/12.01=1.432/1.432=1*4=4

C13H24N4
User Er Mayank
by
7.4k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

8.8m questions

11.4m answers

Other Questions

How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Why is gold preferred as a superior metal over silver and bronze?
What is the evidence of a chemical reaction when the fireworks go off
Link Copied!