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Elemental analysis of a compound, once used as a pesticide, was found to be 74.2% carbon, 8.64% hydrogen, and 17.2% nitrogen. What is the empirical formula of this compound?
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Elemental analysis of a compound, once used as a pesticide, was found to be 74.2% carbon, 8.64% hydrogen, and 17.2% nitrogen. What is the empirical formula of this compound?

User Gogson
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1 Answer

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74.2/16.00=4.6381.432=3.2*4=13
8.64/1.01=8.554/1.432=5.9=6*4=24
17.2/12.01=1.432/1.432=1*4=4

C13H24N4
User Er Mayank
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7.3k points
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