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Work of 2 Joules is done in stretching a spring from its natural length to 19 cm beyond its natural length. What is the force (in Newtons) that holds the spring stretched at the same distance (19 cm)?
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Work of 2 Joules is done in stretching a spring from its natural length to 19 cm beyond its natural length. What is the force (in Newtons) that holds the spring stretched at the same distance (19 cm)?

User Drewrockshard
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Work done ,
Wd = 1/2*kx^2 2joules = 1/2*k*(0.19)^2
find k , spring constant Force that holds the spring stretched = k*0.19 N
User Oliveroneill
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