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Work of 2 Joules is done in stretching a spring from its natural length to 19 cm beyond its natural length. What is the force (in Newtons) that holds the spring stretched at the same distance (19 cm)?
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Dec 27, 2017
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Work of 2 Joules is done in stretching a spring from its natural length to 19 cm beyond its natural length. What is the force (in Newtons) that holds the spring stretched at the same distance (19 cm)?
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Work done ,
Wd = 1/2*kx^2 2joules = 1/2*k*(0.19)^2
find k , spring constant Force that holds the spring stretched = k*0.19 N
Oliveroneill
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Jan 1, 2018
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