Question

How would I solve this problem?

Answer 1

n = 6

Explanation:

`(a^(m))/(a^(n))=a^(m-n)\\\\a^(m)*a^(n)=a^(m+n)\\\\`

`((-4)^(10))/((-4)^(n))=(-4)^(2)*(-4)^(2) \\\\(-4)^(10-n)=(-4)^(2+2)\\\\(-4)^(10-n)=(-4)^(4)`

Compare the exponents,

10 - n = 4

10 = 4 +n

10 - 4 = n

6 = n