Question

1. On six consecutive days, the lowtemperature in a city was -6°C, 3°C, 0°C-1°C, 4°C, and -9°C. What was the meanlow temperature for the six days?

Answer 1

The registered temperatures for the six days are:

-6°C, 3°C, 0°C, -1°C, 4°C and -9°C

To find the mean of the low temperatures given, we need to add all of the temperatures and divide the result by the number of days, in this case, 6 days.

The expression to find the mean is as follows:

`\text{Mean}=((-6)+3+0+(-1)+4+(-9))/(6)`

First, we simplify the numerator of the expression:

`\text{Mean}=(-6+3+0-1+4-9)/(6)`

And solving the additions and subtractions we get:

`\text{Mean}=(-9)/(6)`

Finally, solving the division:

`\text{Mean}=-1.5`

The mean is -1.5°C.

Answer: -1.5°C