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What is the correct value for free energy of this reaction at 300 k?

What is the correct value for free energy of this reaction at 300 k?-example-1
User Niko Fohr
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1 Answer

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Step-by-step explanation:

At constant temperature, the change in Gibbs Free Energy is defined like this:

ΔG = ΔH - T * ΔS

Where ΔG is the change in Gibss Free Energy, ΔH is the change in Enthalpy, T is the temperature in K and ΔS is the change in Entropy.

We are given those values.

ΔH = -92.0 kJ ΔS = -0.198 J/K T = 300 K

If we replace them and solve the equation we will get the answer to our problem.

ΔG = ΔH - T * ΔS

ΔG = -92.0 kJ - 300 K * (-0.198 J/K) * 1 kJ/(1000 J)

ΔG = -92.0 kJ + 0.0594 kJ

ΔG = -91.9 kJ

Answer: ΔG = -91.9 kJ

User Cwtuan
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