Given in the question:
a.) mean = μ = 120
b.) standard deviation = σ = 3
The z - distribution of the 60% is therefore,
P( -z < Z < z ) = 0.60
P( Z < z ) - P( Z < -z ) = 0.60
2*P(Z < z ) - 1 = 0.60
2*P(Z < z ) = 1 + 0.60
P( Z < z ) = 1.60 / 2
P( Z < z ) = 0.80
P( Z < -0.84) = 0.80
Therefore, z = -0.84 and z = 0.84
Using z - score formula:
X = +/-z * σ + μ
At, X = -z * σ + μ
= -0.84 * 4 + 120
= 116.6
At X = +z * σ + μ
= 0.84 * 4 + 120
= 123.4
Therefore,
Lower blood pressure limit = 116.6
Upper blood pressure limit = 123.4