Question

Find the real zero of w (x) =2x^2+10x+13

Answer 1

we have the quadratic equation

w (x) =2x^2+10x+13

Solve the equation using the formula

so

a=2

b=10

c=13

substitute

`w=\frac{-10\pm\sqrt[]{10^2-4(2)(13)}}{2(2)}`
`w=\frac{-10\pm\sqrt[]{-4}}{4}`
`\begin{gathered} w=(-10\pm2i)/(4) \\ w=-2.5\pm0.50i \end{gathered}`

The given equation don't have real zeros

The solutions are complex numbers