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Square root (3) tan 3θ − 1 = 0

User Musemind
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I'm not sure but I'm going to assume that you are finding for the value of theta. If this is correct, the solution would be



√(3) tan3 \alpha \ -1=0


\ tan3 \alpha = (1)/(√(3))


3 \alpha = arctan ( (1)/( √(3) ) )=30


\alpha = 30/3=10

Fyi, there is no theta in the symbols so I just used alpha.

Thus, theta is equal to 10 degrees.
User Mike Honey
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8.9k points

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