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Given the events below, determine which equation correctly calculates the probability of drawing two kings in a row from a standard 52-card deck, without replacement.

Event A: The first card drawn is a king.
Event B: The second card drawn is a king.

A. P(A n B) = P(A) * P(B|A)

B. P(A n B) = P(A) * P(B)

C. P(A n B) = P(A) * P(A|B)

D. P(A n B) = P(B) * P(B|A)

User Renklauf
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2 Answers

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Answer:

A. P (A ∩ B) = P(A) * P(B|A)

Explanation:

got it right

User Oleks
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P of drawing two kings in a row = P of first card is a king * P of second card is a king given that the first card was a king

P (A ∩ B) = P(A) * P(B|A)

Answer: option A.

You can check that this is 4/52 * 3/51
User LPOPYui
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