Permutations.... How many different positive integers of 2 digits each can be made with the digits 2, 4, 5, and 8, if no digit is repeated in a number?

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asked Jun 2, 2017 61.0k views

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Fam · Answer 1 · 2017-06-07T22:52:32+0000

think of it this way:
_ _ (2 digit number)
for the first blank you could have 4 possibilities
for the second blank you could have 3 possibilities
4×3=12
there are 12 possibilities

Permutations.... How many different positive integers of 2 digits each can be made with the digits 2, 4, 5, and 8, if no digit is repeated in a number?

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