Solve for [0,2pi): 3sin^2x-6sinx=0

Rhesa asked Feb 17, 2023

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Rhesa asked Feb 17, 2023

by Rhesa

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22 votes

3 Sin^2 X = 6 sinX

then find

Sin X = 6/3 = 2

Then answer is

X ,doesnt exist

because Sin X is always less than 1

Zubactik answered Feb 22, 2023

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