Question

If a net force of 34.3 N is required to move the system in the figure to the right 2.3 m in 1.3 seconds what is the systems mass

Answer 1

Mass of the system is 25.2 kg
Calculation:

F=ma

m = F/a where a = m/t^2

a=2.3/(1.3)^2 = 1.36 m/s^2

m=34.3/1.36

m=25.2 Kg

Answer 2

m = 12.6 kg

Step-by-step explanation:

As we know that it covers total distance of 2.3 m in 1.3 s

so we will have

`v_i = 0`

`d = 2.3 m`

`t = 1.3 s`

now we can use kinematics to find the acceleration

`d = v_i t + (1)/(2)at^2`

`2.3 = (1)/(2)a(1.3^2)`

`a = 2.72 m/s^2`

Now we can use Newton's law

`F = ma`

`34.3 = m(2.72)`

`m = 12.6 kg`