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Helium scalpha particles are being cele gode Tecoil Figure 127 xercises 12.6 omplete the following: Find the intercepts and domain and perform the symmetry lest on each of the following byperboles (a) 9x? - 16y2 = 144 (e) + y2 = 1 (g) - 9x + 16y2 = 144 Graph the vertices, foci, endpoints of the conjugate axis, fundamental rectangle, and asymptotes then draw the hyperbola for each equation in problem 1. chord of the partial hyperbola with a (d) 25x - 36 = 900 (1)-25x + 4y = 100 (h) -x + 4y = 16 1. 25x² - 4y2 = 100 (c) 25x2 2.

User Brianandere
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1 Answer

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Given the equation of the hyperbola :


9x^2-16y^2=144

Divide all sides by 144


\begin{gathered} (9x^2)/(144)-(16y^2)/(144)=1 \\ \\ (x^2)/(16)-(y^2)/(9)=1 \\ \\ (x^2)/(4^2)-(y^2)/(3^2)=1 \end{gathered}

The hyperbola has the following :

1) x - intercepts are = ( -4 , 0 ) and ( 4 , 0 )

2) there is no y- intercepts

3) domain = ( -∞ , -4] ∪ [4 , ∞ )

4) lines of symmetry are : x = 0 and y = 0


\begin{gathered} a=4,b=3 \\ c^2=a^2+b^2=4^2+3^2=16+9=25 \\ c=\sqrt[]{25}=5 \end{gathered}

5) foci are the points: (-5 , 0 ) and ( 5 , 0 )

User Tom Klino
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