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The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.​

User Dyno Cris
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Given:

The sum of two terms of GP is 6 and that of first four terms is
(15)/(2).

To find:

The sum of first six terms.​

Solution:

We have,


S_2=6


S_4=(15)/(2)

Sum of first n terms of a GP is


S_n=(a(1-r^n))/(1-r) ...(i)

Putting n=2, we get


S_2=(a(1-r^2))/(1-r)


6=(a(1-r)(1+r))/(1-r)


6=a(1+r) ...(ii)

Putting n=4, we get


S_4=(a(1-r^4))/(1-r)


(15)/(2)=(a(1-r^2)(1+r^2))/(1-r)


(15)/(2)=(a(1+r)(1-r)(1+r^2))/(1-r)


(15)/(2)=6(1+r^2) (Using (ii))

Divide both sides by 6.


(15)/(12)=(1+r^2)


(5)/(4)-1=r^2


(5-4)/(4)=r^2


(1)/(4)=r^2

Taking square root on both sides, we get


\pm \sqrt{(1)/(4)}=r


\pm (1)/(2)=r


\pm 0.5=r

Case 1: If r is positive, then using (ii) we get


6=a(1+0.5)


6=a(1.5)


(6)/(1.5)=a


4=a

The sum of first 6 terms is


S_6=(4(1-(0.5)^6))/((1-0.5))


S_6=(4(1-0.015625))/(0.5)


S_6=8(0.984375)


S_6=7.875

Case 2: If r is negative, then using (ii) we get


6=a(1-0.5)


6=a(0.5)


(6)/(0.5)=a


12=a

The sum of first 6 terms is


S_6=(12(1-(-0.5)^6))/((1+0.5))


S_6=(12(1-0.015625))/(1.5)


S_6=8(0.984375)


S_6=7.875

Therefore, the sum of the first six terms is 7.875.

User Shafiq
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