Question

Find two numbers such that the sum of the first and three times the second is 5 and the sum of the second and two times the first is 8.

Answer 1

first number= 19/5

second number= 2/5

Explanation:

first number= a

second number= b

a+3b=5 equation 1

b+2a=8 equation 2

using equation 2 we have

b=8-2a

using equation 1 we have

a+3(8-2a)=5

a+24-6a=5

24-5=6a-a

19=5a

a=19/5 = first number

so using b=8-2a

we have

b=8-2(19/5)

b=8-(38/5)

b=2/5 = second number