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16 votes
Find the zeros of 6x^2-27x

User Juan Ossa
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2 Answers

8 votes
x=9/2 is correct how wisdom said
User Alveomaster
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4.4k points
4 votes

Answer:

x = 0, 9/2

Explanation:

6x^2 - 27x = 0 (original)

3x(2x - 9) = 0 (factor out GCF of 3x)

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v

(solve each factor (3x and 2x - 9) for x)

3x = 0

x = 0

2x - 9 = 0

2x = 9

x = 9/2

User Jhole
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4.3k points