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A line passes through the points (k+3,-2k) and (4,1) and has a y-intercept of 6. Find the value of k.
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A line passes through the points (k+3,-2k) and (4,1) and has a y-intercept of 6. Find the value of k.

User Kayasa
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1 Answer

3 votes
y = mx + b; b = 6

1 = 4m + 6; m = -5/4

-5/4 = (1 + 2k) / (4 - k - 3) = (2k + 1) / (1 - k)

-5(1 - k) = 4(2k + 1)

5k - 5 = 8k + 4

-3k = 9

k = -3
User Jed Schaaf
by
8.4k points
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