Let x be a random variable representing the weight of a selected egg. Let us assume that the selected eggs are normally distributed. Since we know the population mean and standard deviation, we would determine the z score by applying the formula,
z = (x - mean)/standard deviation
For an egg to be graded as extra large, it's weight must be at least 2.2 ounces. The probability of selecting an eggs that weighs at least 2.2 ounces is expressed as
Given that
mean = 1.7
standard deviation = 0.4
x = 2.2
z = (2.2 - 1.7)/0.4 = 1.25
Looking at the normal distribution table, the probability value corresponding to a z score of 1.25 is 0.8944
Given that the total number of eggs is seven dozens,
7 dozens = 7 * 12 = 84
The expected number of extra large eggs that is expected to be selected from 84 eggs is
0.1056 * 84 = 8.8704
Rounding to the nearest whole number, it becomes 9 eggs