Question

How many grams of Fe are needed to create 32.5mol Fe3O4?

Answer 1

5444.89 grams of Fe

Step-by-step explanation:

1) We need the chemical equation for Fe3O4 to find the mole ratio for Fe to Fe3O4. Chemical equation:

3Fe+4H2O → Fe3O4+4H2

The mole ratio of Fe to Fe3O4 is 3:1

2) Now, we find how many grams of Fe are needed to produce 32.5 moles of Fe3O4.

`32.5 moles Fe3O4`
`x (4 mole O)/(1 mole Fe3O4)` = 97.5 moles Fe needed to produce 32.5 moles of Fe3O4

3) Convert 97.5 moles of Fe into grams. The molar mass of Fe is 55.845g.

`97.5 mole Fe`
`x(55.845g Fe)/(1 mole Fe)` = 5444.8875g or 5444.89g.