Question

-3/4x + 5/6y=15 I need to find x and y intercepts please step by step instructions.

Answer 1

Simple....

you have:
`- (3)/(4) x+ (5)/(6) y=15`

To solve for x:


`- (3)/(4) x+ (5)/(6) y=15`

1.) Isolate the variable "x" (Remove y)



`- (3)/(4) x+ (5)/(6) y=15`

`- (5)/(6) y`
`- (5)/(6) y`

Leaving you with....


`(3)/(4) x=-(5)/(6)y +15`

2.) Divide by the variable.....


`( (3)/(4)x )/( (3)/(4) ) = ( -(5)/(6)y+15 )/( (3)/(4) )`

Leaving you with...

x=
`-(10y)/(9) +20`

Now, solve for y.

To solve for y:


`- (3)/(4) x+ (5)/(6) y=15`

1.)Isolate the variable "y" (Remove x)


`- (3)/(4) x+ (5)/(6) y=15`

`+ (3)/(4)`
`+ (3)/(4)`

Leaving you with....


`(5)/(6) y= (3)/(4) x+15`

2.)Divide by the variable.....


`( (5)/(6)y )/( (5)/(6) ) = ( (3)/(4)x+15 )/( (5)/(6) )`

Leaving you with....

y=
`(9x)/(10) +18`

x-intercept: (-20,0)

y-intercept: (0,18)

Thus, your answer.