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-3/4x + 5/6y=15 I need to find x and y intercepts please step by step instructions.

User Luis LL
by
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1 Answer

6 votes
Simple....

you have:
- (3)/(4) x+ (5)/(6) y=15

To solve for x:


- (3)/(4) x+ (5)/(6) y=15

1.) Isolate the variable "x" (Remove y)



- (3)/(4) x+ (5)/(6) y=15

- (5)/(6) y
- (5)/(6) y

Leaving you with....


(3)/(4) x=-(5)/(6)y +15

2.) Divide by the variable.....


( (3)/(4)x )/( (3)/(4) ) = ( -(5)/(6)y+15 )/( (3)/(4) )

Leaving you with...

x=
-(10y)/(9) +20

Now, solve for y.

To solve for y:


- (3)/(4) x+ (5)/(6) y=15

1.)Isolate the variable "y" (Remove x)


- (3)/(4) x+ (5)/(6) y=15

+ (3)/(4)
+ (3)/(4)

Leaving you with....


(5)/(6) y= (3)/(4) x+15

2.)Divide by the variable.....


( (5)/(6)y )/( (5)/(6) ) = ( (3)/(4)x+15 )/( (5)/(6) )

Leaving you with....

y=
(9x)/(10) +18

x-intercept: (-20,0)

y-intercept: (0,18)

Thus, your answer.
User Asped
by
8.2k points

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