62.5k views
4 votes
What value of x is in the solution set of 4x – 12 ≤ 16 + 8x?

2 Answers

3 votes

Answer:

-7

Explanation:

User Nope
by
9.1k points
0 votes

Answer:

x = The set of real numbers greater than or equal to -7

Explanation:

Given:

4x - 12 ≤ 16 + 8x

Here we need to solve for x.

Isolate the variables and constant terms

Subtract 4x on both sides, we get

4x - 4x - 12 ≤ 16 + 8x - 4x

-12≤ 16 + 4x

Now subtract 16 on both sides, we get

-12 - 16 ≤ 16 -16 + 4x

-28 ≤ 4x

This can be written as

4x ≥ -28

Divide both sides by 4, we get

x ≥ -28/4

x ≥ - 7

x = The set of real numbers greater than or equal to -7

User RDotLee
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories