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Three men and five women are waiting to be interviewed for jobs. If they are all selected in random order, find the probability that all men will be interviewed first.

User Basimalla Sebastin
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1 Answer

19 votes
19 votes

Probability is expressed as

number of favorable outcomes/number of total outcomes

From the information given,

number of men = 3

number of women = 5

total number of men and women = 3 + 5 = 8

The favorable outcome in this case is the event of selecting a man. Therefore,

The probability of selecting the first man = 3/8

We are left with 2 men and 7 people. The probability of selecting the second man is 2/7

We are left with 1 man and 6 people. The probability of selecting the third man is 1/6

Therefore, the the probability that all men will be interviewed first is

3/8 x 2/7 x 1/6 = 0.018

the the probability that all men will be interviewed first is 0.018

User Katfang
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