164k views
5 votes
The size of an exponentially growing bacteria colony doubles in 8 hours. How long will it take for the number of bacteria to triple? Give your answer in exact form and decimal form.

User Neil
by
7.9k points

2 Answers

3 votes
population ratio to original value is;
=2^(n/8) = 3
=ln[2^(n/8)]
= (n/8)ln(2)
= ln(3)
answer in exact and decimal form
n = 8ln(3)/ln(2)
n ~ 12.68
hope it helps
User Gsnedders
by
7.9k points
3 votes

Answer:

12.68 hours

Explanation:

The population growth function is,


y=ab^(x)

Where,

a = initial population,

b = growth factor per period,

x = number of periods

Here,

y = 2a, x = 8,


2a = a (b)^8


2=b^8


\implies b = 2^(1)/(8)

Thus, the function that shows the given situation would be,


y=a(2^(1)/(8))^x----(1)

If y = 3a,


3a=a(2^(1)/(8))^x


3=(2^(1)/(8))^x


\implies x = 12.68

Hence, after 12.68 hours the population would be tripled.

User Mc Kevin
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories