210k views
5 votes
25 POINTS!!!! PLEASE EXPLAIN TO ME STEP BY STEP!

Solve the system by substitution.

-x-y-z=-8
-4x+4y+5z=7
2x+2z=4

I am very confused about this. Can someone please explain how to do this?

User Aetherix
by
8.2k points

2 Answers

1 vote
-x-y-z=-8
-x-y-z=-8

Let's solve for x.−x−y−z=−8
Step 1: Add y to both sides.−x−y−z+y=−8+y−x−z=y−8
Step 2: Add z to both sides.−x−z+z=y−8+z−x=y+z−8
Step 3: Divide both sides by -1.−x−1=y+z−8−1x=−y−z+8
Answer: x=−y−z+8
User Jordan Wrong
by
7.8k points
2 votes
easy peassy
so basically what you would try to do is eliminate one type of variable from 2 different equations
look, we have
2x+2z=4
that already has y eliminated
so we just need to eliminate y from another equation

so

we can eliminate the y from the 2nd equation
multiply the first equation by 4 and add to 2nd equation

-4x-4y-4z=-32
-4x+4y+5z=7 +
-8x-0y+1z=-25

-8x+z=-25


we have
-8x+z=-25 and
2x+2z=4

we can elminate the z's
multiply first (top) equation by -2 and add to bottom equaton
16x-2z=50
2x+2z=4 +
18x=54

18x=54
divide both sides by 18
x=3

sub back
2x+2z=4
2(3)+2z=4
6+2z=4
minus 6 both sides
2z=-2
divide 2
z=-1

sub back

-x-y-z=-8
-3-y-(-1)=-8
-3-y+1=-8
-2-y=-8
add 2 to both sides
-y=-6
times -1
y=6


x=3
y=6
z=-1
(x,y,z)
(3,6,-1)
User DoamnaT
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories