Then
4 | x + 1| + 2 > 6
Substract 2 , at left and right
4 |x+1 | > 6-2 = 4
Now divide by 4
(4 |x + 1| )/4 > 4/4
Then
| x + 1| > 1
Now solve this equation, by way of 2 equations
x + 1 > 1
and
- (x + 1) < 1
Solution for first iis
x > 1 - 1
x > 0
And solution for second inequality is
- x - 1 < 1
x < -1 - 1
x < -2
THEN ANSWER interval for this is
(-OO, -2) U (0, OO)
ANSWER IS OPTION B)
Interval notation is
x > 0 ( 0, infinite)
x < -2 ( - infinite, -2)