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A standard penetration test has been conducted on a coarse sand at a depth of 16 ft below the ground surface. The blow counts obtained in the field were as follows:

0-6 in. 4 blows; 6-12 in.: 6 blows; 12-18 in.: 6 blows. The tests were conducted using a USA-style donut hammer in a 6-in diameter boring using a standard sampler with the liner installed. The vertical effective stress at the test depth was 1500 lb/ft^2. Determine N1.60.

User Daharon
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1 Answer

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Solution :

Given :

The number of blows is given as :

0 - 6 inch = 4 blows

6 - 12 inch = 6 blows

12 - 18 inch = 6 blows

The vertical effective stress
$=1500 \ lb/ft^2$


$= 71.82 \ kN/m^2$


$ \sim 72 \ kN/m^2 $

Now,


$N_1=N_0 \left(\frac{350}{\bar{\sigma}+70} \right)$


$N_1 = $ corrected N - value of overburden


$\bar{\sigma}=$ effective stress at level of test

0 - 6 inch,
$N_1=4 \left((350)/(72+70) \right)$

= 9.86

6 - 12 inch,
$N_1=6 \left((350)/(72+70) \right) $

= 14.8

12 - 18 inch,
$N_1=6 \left((350)/(72+70) \right) $

= 14.8


$N_(avg)=(9.86+14.8+14.8)/(3)$

= 13.14

= 13

User Dur
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