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Find the sum of the first 8 terms of the sequence: -5. 15, -45, 135, .......

1 Answer

6 votes
sum of geometric sequence

for the sum where the initial value is a₁ and the common ratio is r and the term is n


S_n= (a_1(1-r^n))/(1-r)

common ratio is -3
-5 times -3 is 15, -15 times -3=-45 etc
first term is -5
and we want the 8th term


S_8= (-5(1-(-3)^8))/(1-(-3))

S_8= (-5(1-6561))/(1+3)

S_8= (-5(-6560))/(4)

S_8= (32800)/(4)

S_8= 8200


the sum is 8200
User Justmaker
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