Question

If r(x) = 3x – 1 and s(x) = 2x + 1, which expression is equivalent to (r/s)(6)?

Answer 1

A. 3(6)-1/2(6)+1 this is the answer

Answer 2

`(3(6)-1)/(2(6)+1)\text{ or }(18-1)/(12+1)\text{ or }(17)/(13)`

Explanation:

Given functions,

`r(x) = 3x -1------(1)`

`s(x) = 2x + 1-----(2)`

`\because (r)/(s)(6)=(r(x))/(s(x))`

From equation (1) and (2),

`(r)/(s)(x)=(3x-1)/(2x+1)`

Put x = 6,

`(r)/(s)(6) = (3(6)-1)/(2(6)+1)=(18-1)/(12+1)=(17)/(13)`