yas
binomial theorem
ok so
for (a+b)^n
the first term is a^n
2nd term has a^(n-1)
x^7 is 1 less than x^8
we know that it is the 2nd term
to find the nth term of a bionial expansion (a+b)^n
you do,
the nth term is k, so then you do
k-1=z
then
the coeficint of that is
![\left[\begin{array}{ccc}n\\z\end{array}\right] = (n!)/(z!(n-z)!)](https://img.qammunity.org/2017/formulas/mathematics/high-school/cldpxeus67dw2sdoc1ymqmx6gib55u0fqp.png)
so n=8
k=2
2-1=1
z=1
![\left[\begin{array}{ccc}8\\1\end{array}\right] = (8!)/(1!(8-1)!)](https://img.qammunity.org/2017/formulas/mathematics/high-school/fs1saxkjp1sz2j8ykiq1lc818xx21nccfn.png)
=

the coefient is 8