Sodium Hydroxyde + Iron (III) Nitrate ---->
This is a double replacement reaction where there is a precipitation. We can exchange the ions to get the products.
Sodium Hydroxide + Iron (III) Nitrate ----> Sodium Nitrate + Iron (III) Hydroxide
Now we have to find the formula of these compounds. We will use the name of the ions.
Sodium = Na⁺
Hydroxide = OH⁻
Iron (III) = Fe³⁺
Nitrate = NO₃⁻
With these ions we can form these compounds:
Sodium Hydroxide = NaOH
Iron (III) Nitrate = Fe(NO₃)₃
Sodium Nitrate = NaNO₃
Iron (III) Hydroxide = Fe(OH)₃
NaOH + Fe(NO₃)₃ ---> NaNO₃ + Fe(OH)₃
To get the molecular equation we have to see if the equation is balanced and also we have to add the states. All the compounds are aqueous solutions except from Fe(OH)₃ that is an insoluble compound, so it is a solid.
NaOH (aq) + Fe(NO₃)₃ (aq) ---> NaNO₃ (aq) + Fe(OH)₃ (s)
And now we can balance it. We have 3 OH on the right and just one on the left. We can change the coefficient for NaOH and write a 3 there.
3 NaOH (aq) + Fe(NO₃)₃ (aq) ---> NaNO₃ (aq) + Fe(OH)₃ (s)
We have 3 atoms of Na on the left and just one on the right. We can change the coefficient for NaNO₃ and write a 3 in front of it.
3 NaOH (aq) + Fe(NO₃)₃ (aq) ---> 3 NaNO₃ (aq) + Fe(OH)₃ (s)
And finally the equation is balanced.
Answer: Molecular equation:
3 NaOH (aq) + Fe(NO₃)₃ (aq) ---> 3 NaNO₃ (aq) + Fe(OH)₃ (s)
To write the complete ionic equation we have to split these compounds back into their ions.
3 Na⁺ (aq) + 3 OH⁻ (aq) + Fe³⁺ (aq) + 3 NO₃⁻ (aq) ---> 3 Na⁺ (aq) + 3 NO₃⁻ (aq) + Fe(OH)₃ (s)
Fe(OH)₃ will not dissolve since it is insoluble and is the precipitate.
Answer: Total ionic equation:
3 Na⁺ (aq) + 3 OH⁻ (aq) + Fe³⁺ (aq) + 3 NO₃⁻ (aq) ---> 3 Na⁺ (aq) + 3 NO₃⁻ (aq) + Fe(OH)₃ (s)
To get the net ionic equation we cancel out the ions that are on both sides of the equation:
3 OH⁻ (aq) + Fe³⁺ (aq) ---> Fe(OH)₃ (s)
Answer: Net ionic equation:
3 OH⁻ (aq) + Fe³⁺ (aq) ---> Fe(OH)₃ (s)