Question

Write the equation of a line going through the points (4,2) and (7,-3).

Answer 1

Equation of the straight line passing through the point ( 4,2) and (7,-3) is

5 x + 4y - 28=0

Explanation:

Step(i):-

Given points are ( 4,2 0 and ( 7,-3)

Slope of the line

`m = (y_(2)-y_(1) )/(x_(2) -x_(1) ) = (-3-2)/(7-4) = (-5)/(4)`

Step(ii):-

Equation of the straight line passing through the point ( 4,2) and

having slope m =
`(-5)/(4)`

y - y₁ = m( x- x₁ )

`y - 2 = (-5)/(4) ( x-4)`

4( y -2) = -5( x-4)

4 y - 8 = - 5x +20

5x +4y -8 -20=0

5 x + 4y - 28=0

Final answer:-

Equation of the straight line passing through the point ( 4,2) and (7,-3) is

5 x + 4y - 28=0