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Find the equation of the line
Passes (2,2) and has slope 6

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Point-slope form of a line: we need a point (x₀,y₀) and the slope "m":
y-y₀=m(x-x₀)

Data:
(2,2)
m=6

Therefore:
y-2=6(x-2) (Point-slope form)
y-2=6x-12
y=6x-12+2
y=6x-10 (slope-intercepted form "y=mx+b")

Answer: the equation of the line in Point-slope form would be :
y-2=6(x-2), and the equation of the line in slope-intercept form would be: y=6x-10


User Abdul Wadood
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