Point-slope form of a line: we need a point (x₀,y₀) and the slope "m":
y-y₀=m(x-x₀)
Data:
(2,2)
m=6
Therefore:
y-2=6(x-2) (Point-slope form)
y-2=6x-12
y=6x-12+2
y=6x-10 (slope-intercepted form "y=mx+b")
Answer: the equation of the line in Point-slope form would be :
y-2=6(x-2), and the equation of the line in slope-intercept form would be: y=6x-10