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The total profit made by an engineering firm is given by the function p=x^2 - 24x +5000 where x is the number of clients the firm has and p is the profit.

1. Find the maximum profit made by the company.

2. How many clients are necessary to reach the profit outlined in part one?

1 Answer

8 votes

Answer:


5144


12

Explanation:

The function
p=x^2-24x+5000 is incorrect as its roots are imaginary
b^2-4ac=576-4* 5000=-19424<0.

So, the correct function is


p=-x^2+24x+5000

Differentiating with respect to
x we get


p'=-2x+24

Equating with zero


0=-2x+24\\\Rightarrow x=(24)/(2)\\\Rightarrow x=12

Double derivative of the function


p''=-2<0

So, the function is maximum at
x=12

Maximum profit is


p=-x^2+24x+5000=-12^2+24* 12+5000\\\Rightarrow p=5144

The maximum profit made by the company is
5144

The number of clients required to make the maximum profit is
12.

User Andrew Newby
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