A container has 50 electronic components, of which 10 are defective. If 8 components are drawn at random from the container, what is the probability that exactly 3 of them are defective?

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asked Jun 10, 2015 177k views

5 votes

A container has 50 electronic components, of which 10 are defective.

If 8 components are drawn at random from the container, what is the probability that exactly 3 of them are defective?

Mathematics
high-school

Dannysauer asked

by Dannysauer

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2 Answers

1 vote

(10/50) * (3/8) = .075
.075 * 100 = 7.5% chance of this happening

Thuga answered Jun 12, 2015

by Thuga

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7 votes

Answer:

$0.1468 \\= 0.147$

Explanation:

A container has 50 electronic components, of which 10 are defective. If 8 components-example-1

Wayoshi answered Jun 15, 2015

by Wayoshi

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