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A container has 50 electronic components, of which 10 are defective.

If 8 components are drawn at random from the container, what is the probability that exactly 3 of them are defective?

User Dannysauer
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2 Answers

1 vote
(10/50) * (3/8) = .075
.075 * 100 = 7.5% chance of this happening
User Thuga
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8.7k points
7 votes

Answer:


0.1468 \\= 0.147

Explanation:

A container has 50 electronic components, of which 10 are defective. If 8 components-example-1
User Wayoshi
by
7.8k points

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