Question

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Answer 1

`Zn_((s))+HCl_((aq))\text{ }\rightarrow ZnCl_(2(aq))+H_(2(g))`

Step-by-step explanation:

Here, we want to get the result of zinc reacting with hydrochloric acid

When metallic elements react with hydrochloric acid, the metallic salt and hydrogen gas is formed

What happens in this scenario is that the hydrogen in the mineral acid is displaced by the metal to give the metallic salt and hydrogen gas.

In displacing the hydrogen, the metal must be higher in place than hydrogen in the activity or electrochemical series. Metals that are lesser in place than hydrogen will not be able to displace hydrogen and as such, there will be no reaction

In this present scenario, zinc is higher than hydrogen in the activity series. Thus, it is expected to displace the hydrogen. Thus, on reacting zinc metal with hydrochloric acid, zinc chloride salt and hydrogen gas are the products formed

We have the reaction equation as shown below:

`Zn_((s))+HCl_((aq))\text{ }\rightarrow ZnCl_(2(aq))+H_(2(g))`