Question

Convert -6- 8i into polar form, r(cos(0) + i sin(0)):

Answer 1

Explanation:

We have the following expression of a complex number:

`-6-8i`

We must convert it to its polar form, for this we must calculate its magnitude and angle, like this:

`\begin{gathered} \text{ Magnitude: }||-6-8i||=√((-6)^2+(-8)^2)=√(36+64)=√(100)=10 \\ \\ \text{ Angle: }\theta=\arctan\left((-8)/(-6)\right)=53.13\degree+180\degree=233.13\degree \\ \\ \text{ Therefore:} \\ \\ 10(\cos(233.13\degree)+i\sin(233.13\degree)) \end{gathered}`