Question

how many mL of C16H34 are needed to react for complete combustion with 0.05 mol O2. The density of C16H34 is 0.80g/mL

Answer 1

The balanced chemical reaction would be expressed:

C16H34 + 49/2O2 = 16CO2 + 17H2O

We are given the amount of O2 to be used up for the reaction. We will use this amount as the starting point for the calculations.

0.05 mol O2 ( 1 mol C16H34 / 49/2 mol O2 ) ( 226.5 g C16H34 / 1 mol C16H34) ( 1 mL / 0.80 g ) = 0.58 mL C16H34