Question

The rectangle shown has a perimeter of 34 cm and the given area. Its length is 5 more than twice its width. Write and solve a system of equations to find the dimensions of the rectangle.

Answer 1

Let the width be w, then the length is 2w + 5
Perimeter = 2(length + width)
34 = 2(2w + 5 + w) = 2(3w + 5)
3w + 5 = 34/2 = 17
3w = 17 - 5 = 12
w = 12/3 = 4

Therefore, the width is 4 cm and the length is 2(4) + 5 = 8 + 5 = 13 cm.