Question

A shipping container is in the shape of a right rectangular prism with a length of 12 feet, a width of 13.5 feet and a height of 15 feet. The container is completely filled with contents that weigh on average, 0,46 pound per cubic foot. What is the weight of the contents in the container, to the nearest pound?

Answer 1

The weight of the contents in the container is;

`1142\text{ pounds}`

Step-by-step explanation:

Given that the shipping container is in the shape of a right rectangular prism with a length of 12 feet, a width of 13.5 feet, and a height of 15 feet.

`\begin{gathered} l=12\text{ ft} \\ w=13.5\text{ ft} \\ h=15\text{ ft} \end{gathered}`

Recall that the volume of a right rectangular prism can be calculated using the formula;

`V=l* w* h`

substituting the given values;

`\begin{gathered} V=12*13.5*15ft^3 \\ V=2430\text{ cubic feet} \end{gathered}`

from the question,the container is completely filled with contents that weigh an average, 0.47 pound per cubic foot.

`\text{density = 0.47 lb/ft}^3`

The weight of the content would be;

`\text{mass = density }*\text{ volume}`

substituting the density and volume of contents, we have;

`\begin{gathered} mass=0.47*2430 \\ =1142.1\text{ pounds} \\ \approx1142\text{ pounds} \end{gathered}`

Therefore, the weight of the contents in the container is;

`1142\text{ pounds}`