Question

Y is inversely proportional to the square of x. If Y = 9 when x = 2,then what is Y, when x is 10?9O 25OO252

Answer 1

Step 1

Y is inversely proportional to the square root of x.

`y\text{ = }(k)/(x^2)`

Step 2

Find the value of k if Y = 9 when x = 2.

`\begin{gathered} y\text{ = }(k)/(x^2) \\ \\ 9\text{ = }(k)/(2^2) \\ \\ k\text{ = 9}*4\text{ = 36} \end{gathered}`

Step 3

What is Y, when x is 10?

`\begin{gathered} y\text{ = }(36)/(10^2) \\ \\ y\text{ = }(36)/(100) \\ \\ y\text{ = }(9)/(25) \end{gathered}`

Final answer

`(9)/(25)`