4,248 views
35 votes
35 votes
Homework:Chapter 08.4Question 5, 8.4.C-3HW Score: 18%, 4.5 of 25 pointsPoints: 0.5 of 1Question content area topPart 1Find the area of the shaded portion of the figure

Homework:Chapter 08.4Question 5, 8.4.C-3HW Score: 18%, 4.5 of 25 pointsPoints: 0.5 of-example-1
User Peter Gerber
by
2.0k points

1 Answer

15 votes
15 votes

In the given figure the diameter of the larger circle is 2.5 inches

and the diameter of the smaller circle is 0.8 inches.

The radius is given as, r = d/2 where d is the diameter.

Then,

the radius of the larger circle = R = 2.5/2 inches = 1.25 inches

and the radius of the smaller circle is = r = 0.8/2 inches = 0.4 inches

Now the area of the circle is given as


\begin{gathered} A=\pi r^2 \\ where\text{ r is the radius of the circle} \end{gathered}

So the area of the shaded portion will be


\begin{gathered} Required\text{ area=}\pi R^2-\pi r^2 \\ Required\text{ area = }\pi[R^2-r^2]=(22)/(7)*[1.25^2-0.4^2] \\ Required\text{ area =3.14}*1.4025\text{ sq inches} \\ Required\text{ area = 4.40385 sq inches} \end{gathered}

Hence the area of the shaded portion will be 4.40385 sq inches.

User Dixuji
by
3.0k points