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Find an equation of the line that bisects the acute angles formed by the lines with equations 2x+y-5=0 and 3x-2y+6=0
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Find an equation of the line that bisects the acute angles formed by the lines with equations 2x+y-5=0 and 3x-2y+6=0

User Korteee
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1 Answer

5 votes
The solving for the first one should be like this


2x+y-5/sqrt 2^2 1^2=2x+y-5/sqrt5
And the next part
3x-2y+6/sqrt 3^2 -2^2=3x-2y+6/sqrt13

After these manipulations just multiply them

(2sqrt13-3sqrt5)x+(sqrt13+2sqrt5) y-5sqrt13-6sqrt5=0
And finally you need to square and simplify for the completed answer
User Eric Scrivner
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8.0k points
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