Question

Find the equation of the line that passes through point (-2,5) and is parallel to y=-3x+7 also write in slope-intercept form without any spaces

Answer 1

y = - 3x - 1

Step-by-step explanation

Recall: Parallel lines have the same slope.

The slope-intercept form is given as: y = mx + c

where m is the slope and c is the y-intercept.

From the given equation y = -3x + 7,

slope (m) = - 3

Now, the equation of the new line is:

y = -3x + c

Insert the point (-2, 5) as (x, y) to determine the 'c'

5 = -3(-2) + c

5 = 6 + c

subtract 6 from both sides

5 - 6 = 6 + c - 6

c = - 1

Hence, the equation of the line that passes through point (-2,5) and is parallel to y=-3x+7 is y = - 3x - 1.