Question

How many moles of a gas sample are in 2.5 L container at 373 K and 203 kPa?

Answer 1

Step-by-step explanation:

The given data is as follows.

P = 203 k Pa, V = 2.5 L

T = 373 K, n = ?

R = 0.0821 atm L/ K mol

Convert pressure from k Pa to atm as follows.

`(203 k Pa)/(1) * (1 atm)/(101.3 k Pa)` = 2.00 atm

Now, using the ideal gas equation we will calculate the number of moles as follows.

PV = nRT

n =
`(PV)/(RT)`

=
`(2.00 atm * 2.5 L)/(0.0821 atm L/ K mol * 373 K)`

=
`(5)/(30.62)` mol

= 0.163 mol

Thus, we can conclude that number of moles in the given gas sample is 0.163 mol.

Answer 2

answer is option d that is 0.17.