Question

it was determined through analysis that a compound, sodium carbonate with a molar mass of 263 g/mol contained 68.4% water. determine the toilet number of water molecules in this hydrate

Answer 1

`molec_(water)=6.016*10^(24)molecules`

Step-by-step explanation:

Hi, here I explain step by step:

1) You have 263 g/mol and 68.4% of that (in weight) is water. So for 1 mol:

`m_(water)=0.684*263 g`

`m_(water)=179.89 g`

2) A mol of water molecules weights 18 g/mol (16 g/mol of oxygen and 2g/mol of hydrogen):

`n_(water)=(179.89g)/(18g/mol)`

`n_(water)=9.99 mol`

3) Knowing Avogadro's number: 6.022*10^23 molec/mol:

`molec_(water)=9.99 mol*6.022*10^(23)molec/mol`

`molec_(water)=6.016*10^2^4molec`